-x^2-x=-18

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Solution for -x^2-x=-18 equation:



-x^2-x=-18
We move all terms to the left:
-x^2-x-(-18)=0
We add all the numbers together, and all the variables
-1x^2-1x+18=0
a = -1; b = -1; c = +18;
Δ = b2-4ac
Δ = -12-4·(-1)·18
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{73}}{2*-1}=\frac{1-\sqrt{73}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{73}}{2*-1}=\frac{1+\sqrt{73}}{-2} $

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